使用
replace与
dict更换和
regex=True:
df['url'] = df['url'].replace({'icashier.alipay.com': 'aliexpress.com'}, regex=True)print (df) url0 aliexpress.com/catalog/2758186/detail.aspx1 aliexpress.com/catalog/2758186/detail.aspx2 aliexpress.com/catalog/2758186/detail.aspx3 vk.com