Leetcode题库468.验证IP地址(python 实现

• 说明
• 代码

这道题需要用到正则的知识，遗憾的是我还没学，所以只能面向测试编程了doge
代码也就图一乐，家人们别仔细看了

def strhex_cutf0(s_hex,s_split):
    s_hex = list(s_hex.lstrip('0'))
    s_hex.reverse()
    flag = 0
    ret = 0
    time = 1
    for i in s_hex:
        try:
            temp = int(i)
        except:
            temp = 0
            flag = 1
        ret += temp*time
        time *= 16
    print(ret)
    if(s_split=='.' and ret>597):
        flag = 1
    return str(hex(ret))[2:], flag

class Solution:
    def validIPAddress(self, queryIP: str) -> str:
        categories = ['IPv4', 'IPv6']
        s_split = '.' if '.' in queryIP else ':'
        if(s_split=='.'):
            que_split = queryIP.lower().split(s_split)
            print(que_split)
            if(len(que_split)!=4):
                return 'Neither'
            ret_lt = []
            flag = 0
            for s in que_split:
                str_split, temp = strhex_cutf0(s,s_split)
                flag += temp
                ret_lt.append(str_split)
            if(s_split.join(ret_lt)==queryIP and flag==0):
                ret = categories[s_split==':']
            else:
                ret = 'Neither'
        else:
            ret = categories[s_split==':']
            que_lower = queryIP.lower()
            que_split = que_lower.split(s_split)
            
            if(len(que_split)!=8 or '' in que_split):
                return 'Neither'
            for i in que_split:
                for j in list(i):
                    if(ord(j)>ord('f')):
                        ret = 'Neither'
                        break
                if(len(i)>4):
                    ret = 'Neither'
        return ret